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The above roof truss is exposed to a snow load. Somebody else has already determined what fraction of the snow lying on the entire roof has to be carried by the truss shown in the above figure, namely 2400 N (about 500 lbs). Because for the method of joints we have to assign these 2400 N to the individual joints the force P=600 N arises in the above figure assuming that the snow load is evenly distributed across the roof.
Use the Method of Section to determine the force in the member 23.
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Last modified : Sun Aug 10, 1997